Question

81x^3(50x^2-98)/27x^2(5x+7)

Answer 1

$\huge\boxed{\texttt{\fcolorbox{red}{aqua}{Hey Mate!!!}}}$
$<b><i><font face=Copper black size=4 color=blue>$
Here is your answer

$\frac{81 {x}^{3} (50 {x}^{2} - 98) }{27 {x}^{2} (5x + 7)} \\ \\ = \frac{3x \times 2(25 {x}^{2} - 49) }{(5x + 7)} \\ \\ = \frac{6x((5 {x})^{2} - {7}^{2} ) }{(5x + 7)} \\ \\ = \frac{6x(5x + 7)(5x - 7)}{(5x + 7)} \\ \\ = 6x(5x - 7) \\ \\ = 30 {x}^{2} - 42x$
$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\:helps\: you}}}}}}}}}}}}}}}$

$\huge\boxed{\texttt{\fcolorbox{Red}{yellow}{Be brainly!!!}}}$

$<marquee>$
$\huge\bf{\red{\huge{\bf{@.....rajeev378}}}}$

Answer 2

ANSWER IS

$\frac{81 {x}^{3}(50 {x}^{2} - 98) }{27 {x}^{2} (5x + 7)} \\ \\ = \frac{3x \times 2(25 {x}^{2} - 49) }{(5x + 7)} \\ = \frac{6x(5x + 7)(5x - 7)}{(5x + 7)} \\ = 6x(5x - 7)$
Thanks