Question

[¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯830÷166 ×{452+2 ( 172+136÷34−127 )}]

Answer 1

Answer:

[830÷166 ×{452+2 ( 172+136÷34−127 )}] = 2750

Step-by-step explanation:

we have find the value of

[830÷166 ×{452+2 ( 172+136÷34−127 )}]

We first solve the small brackets and inside the brackets we use DMAS rule of mathematics that is we first performs the division,then multiplication then addition and then subtraction.

= [830÷166 ×{452+2 ( 172+136÷34−127 )}]

= [830÷166 ×{452+2 ( 172+ 4 − 127 )}]

= [830÷166 ×{452+2 ( 49 )}]

= [830÷166 ×{452+ 98}]

= [830÷166 ×{452+ 98}]

= [830÷166 ×550]

= [5 ×550]

= 2750

Hence

[830÷166 ×{452+2 ( 172+136÷34−127 )}] = 2750