Question

830 কে এমন দুটি অংশে ভাগ করি যেন একটি অংশের শতকরা 30 অপর অংশের শতকরা 40 অপেক্ষা 4 বেশি হয়।​

Answer 1

let they are X and (830-x)

now ,30%of X is =30x/100=3x/10

and 40%of (830-x)

$= \frac{40}{100} \times (830 - x) \\ = \frac{2}{5} \times (830 - x) \\ = 332 - \frac{2 x }{5}$

now according to the problem.....

$\frac{3x}{10} = (332 - \frac{2x}{5} ) + 4 \\ = > \frac{3x}{10} + \frac{2x}{5} = 336 \\ = > \frac{3x + 4x}{10} = 336 \\ = > 7x = 3360 \\ = > x = \frac{3360}{7} \\ = > x = 480$

so the numbers are 480 and (830-480)=350

hope this helps you ......