Math, asked by princess3790, 10 months ago

84^628 + 625^231 × 694 ^157​

Answers

Answered by SudipSamanta
0

Answer:

I am not able to give the answer of your questions.

Answered by harendrachoubay
0

The unit digit of84^{628}+625^{231}\times 694^{157} is "6".

Step-by-step explanation:

We have,

84^{628}+625^{231}\times 694^{157}

= 4^{628}+5^{231}+4^{157}

4^{628}=6, because 628 is divisible by 2.

The unit digit of:

5^{231} = 5 and

4^{157} = 4^{2\times 78+1} =4^{1} =4

∴ The unit digit of84^{628}+625^{231}\times 694^{157}

= 6 + 5 × 4

= 6 + 20 = 26

= 6, is the unit digit.

Hence, the unit digit of84^{628}+625^{231}\times 694^{157} is 6.

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