85 g of Ammonia gas (NH3) is kept at STP
Calculate the number of molecules and atoms present in this sample?
What is the volume of this sample?
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Answer:
no. of moles =5
no. of molecules = 5Na
no. of atoms =15 Na
vol of gas =5×22.4L = 112L
Explanation:
no. of moles = gives mass/molar mass=85/17=5
no of atoms = no of moles×Na×total atoms=5×3×Na=15
no of molecules = moles ×Na= 5Na
volume of gas at stp =moles × 22.4L =112L
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