Question

87. If log 2 = x, log 3 = y and log 5 = 2, then the
value of log 270 is
(A) 2x + 2y + 2
(B) x + y + 22
(C) 2x + y + 2
YD) x + 3y + 2​

Answer 1

Answer:

option D

Step-by-step explanation:

270 = 5×3^3×2

log(270) = log ( 5× 3^3×2)

we have, log(abc)= log a+ log b + log c

=> log 5 + log 3^3 + log 2

=> log 5+ 3log 3+ log 2 = x + 3y + 2