Physics, asked by umak242000, 1 month ago

87. The efficiency of a Car not engine working between
temperatures T1 and T2 (T; <T2) is
T₂-T
Ti
TI-T2
(b)
T₂
(a)
T₂-T
II-T₂
(d)
T
[Ans.cl
(c) T2
The temnerature of the​

Answers

Answered by itzIntrovert
3

\huge\bigstar\underline\pink{Answer}

★ source is always taken for High Temperature and Sink of Low temperature

★ here, T1 < T2

so, efficiency will be ( T2 - T1 )/ T2

\huge\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{\ddot{\smile}}

Answered by FairyLight
2

Answer:

Source is always taken for high temperature & sink of low temperature. Here, T1 < T2. So, efficiency will be ( T2 - T1 ) / T2 Strong.

Explanation:

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