Math, asked by avani1902, 11 months ago

8751 and 12560using euclid division algorithm by hcf

Answers

Answered by sanju9546
0
here is ur ans

8751=3809×2+1122

3089=1122×3+443

1122=443×2+236

443=236×1+207

236=207×1+29

207=29×7+6

29=6×4+5

6=5×1+1

5=1×5+0

so hcf IS "ONE"
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