8751 and 12560using euclid division algorithm by hcf
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here is ur ans
8751=3809×2+1122
3089=1122×3+443
1122=443×2+236
443=236×1+207
236=207×1+29
207=29×7+6
29=6×4+5
6=5×1+1
5=1×5+0
so hcf IS "ONE"
8751=3809×2+1122
3089=1122×3+443
1122=443×2+236
443=236×1+207
236=207×1+29
207=29×7+6
29=6×4+5
6=5×1+1
5=1×5+0
so hcf IS "ONE"
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