Question

88 g of CO2 are confined to a 6 L flask at 37°C.
Calculate its pressure using van der Waals' equation.
Given, a = 4.17 atm L² mol-², b = 0.038 L mol-¹​

Answer 1

Answer:

p - a / v² ( v - b ) = RT ,. ,wh

Explanation:

p = ? , a = 4.17 atmL² mol _² , b= 0.038 L mol_¹ ,volume = 6 L now according to Vander waals equation ( p - 4.17 atm L ² mol 10 / 6 L² ) × { 6L - 0.038 L mol ¹ }= R × T. ( p - 4. 17 atm mol¹ / 36 ) × { 5.962 L mol¹} = 8.314 × 310.15 Kelvin. p - 0.086× 5.962 atm mol_3 = 8.314 × 310.15 kelvin. p = 2578711160 - 512732. p = 2578198428 j k¹ mol ¹ answer. where value of R = 8.3144j k¹ mol -²