Question

A particle covers 10 m in first 5 S and 10 m in next 3 S. Assuming constant
acceleration. Find the initial speed, acceleration and distance covered in next
28. (Application to Daily life Concern and Biodiversity) (T.Q.12)​

Answer 1

Answer:It is given that a particle covers 10m in first 5s and 10m in next 3s. so using the equation of motion

Case I

s=ut+  

2

1

​  

at  

2

 

10=5u+  

2

1

​  

a(5)  

2

 

20=10u+25a

4=2u+5a..............(1)

Case 2

In next 3s the particle covers more 10m distance. So

20=8u+  

2

1

​  

a(8)  

2

 

5=2u+8a.........(2)

On solving equation (1) and (2)

4=2u+5a

5=2u+8a

a=  

3

1

​  

m/s  

2

 

Put the value of a in equation (1)

u=  

6

7

​  

m/s

Now to find distance in next 10 s. total time will be 10s

s=  

6

7

​  

×10+  

2

1

​  

×  

3

1

​  

×(10)  

2

 

s=28.33m

Distance travelled in next 2 sec

s=28.33−20=8.33m

Explanation:

Answer 2

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