Question

887 cal of heat is added to 5.00 g ice at -20.0 degree c. What is the final temperature of the water?

Answer 1

Answer:

This is shown by the inversely proportional curve in (C).

If done in joules, 5.00 g of ice to water

= 5.00 × 3.34 × 102 g/J

= 1.67 × 103 J. 1 g at 4°C to 100°C

= ∆ temp = 96°