Question

if one root of the quadratic equation 6x^2-x-k=0 is 2/3,then find the value of k

Answer 1

Heya !
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★Quadratic Equations ★
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=> Given Equation :

→ 6x² - x - k = 0

°•° One root of the equation is ⅔ . Hence we can substitute x as ⅔ in the equation .

=> Putting x = ⅔ we have ,

=> 6 ( ⅔ )² - ⅔ - k = 0

=> 6 ( 4/9 ) - ⅔ - k = 0

=> 8/3 - 2/3 - k = 0

=> 6/3 - k = 0

→ 2 - k = 0

=> - k = -2

•°• k = 2

★Thus, the value of K is 2 !

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Answer 2

Answer:

Step-by-step explanation:

6x²-x-k=0

X=2/3 is zero

So 6×(4/9)-(2/3)=K

=8/3-2/3=k

6/3=2=K