if one root of the quadratic equation 6x^2-x-k=0 is 2/3,then find the value of k
Answers
Answered by
196
Heya !
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★Quadratic Equations ★
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=> Given Equation :
→ 6x² - x - k = 0
°•° One root of the equation is ⅔ . Hence we can substitute x as ⅔ in the equation .
=> Putting x = ⅔ we have ,
=> 6 ( ⅔ )² - ⅔ - k = 0
=> 6 ( 4/9 ) - ⅔ - k = 0
=> 8/3 - 2/3 - k = 0
=> 6/3 - k = 0
→ 2 - k = 0
=> - k = -2
•°• k = 2
★Thus, the value of K is 2 !
_____________________________________________________
_____
______________________________________________________
★Quadratic Equations ★
_____________________________________________________
=> Given Equation :
→ 6x² - x - k = 0
°•° One root of the equation is ⅔ . Hence we can substitute x as ⅔ in the equation .
=> Putting x = ⅔ we have ,
=> 6 ( ⅔ )² - ⅔ - k = 0
=> 6 ( 4/9 ) - ⅔ - k = 0
=> 8/3 - 2/3 - k = 0
=> 6/3 - k = 0
→ 2 - k = 0
=> - k = -2
•°• k = 2
★Thus, the value of K is 2 !
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anshita1225198050:
Thanks for helping me
Answered by
38
Answer:
Step-by-step explanation:
6x²-x-k=0
X=2/3 is zero
So 6×(4/9)-(2/3)=K
=8/3-2/3=k
6/3=2=K
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