Question

88Ra226 experiences three alpha decay .find the number of neutrons in the daughter element.

Don't spam....​

Answer 1

Answer:

Solution :

α-decay : zXA→z−2YA−4+2He4  

3α-decay:

zXA→z−6YA−12+3(2He4)

∴88Ra226→82Pb214+32He4(or)

88Ra226→82X214+32He4

Explanation: HOW MANY TIMES U WILL ASK THE SAME QUESTION

Answer 2

Answer:

how are you...............