Question

89) A man is 32 years olden than ho son. Ten years ago he was three times as old as his son was then, find the present age of the
man and his son.​

Answer 1

Answer:

Father's age = 58yrs

Son's age = 26yrs

Step-by-step explanation:

Let Father = X

Son = Y

Given, X=Y+32__________________1

Ten yrs ago, (X-10)=3(Y-10)_________2

Put 1 on 2

(Y+32-10)=3(Y-10)

Y+22=3(Y-10)

Y+22=3Y-30

30+22=3Y-Y

52=2Y

Y=26yrs

X=26+32=58yrs

So Father's age = 58yrs

Son's age = 26yrs

Answer 2

Answer:

Step-by-step explanation:

Son's age=x

Father's age=x+32

10 years ago

Sons age=x-10

Father's age=(x+32)-10

X+32-10=3(x-10)

X+22=3x-30

22+30=3x-x

2x=52

X=52/2=26

Son's age=26

Father's age=26+32=58 years.