Question

896 ml of a mixture of CO & CO weight 1.28 g at NTP. Calculate the volume of CO2 in the mix at NTP

Answer 1

As we know that:
PV = n R T
M = wRT / PV
M = 1.28 * 0.0821 * 273.15 / 1 * 896 * 1/1000 * L/ mL
M = 1.28 * 0.0821 * 273.15 * 1000 / 1 * 896
M = 32 g / mol
1 mole of mixture weighs to 32  g
adding weight to get answer
28 x + 44 ( 1 - x ) = 32
44 - 16 x = 32
x = 0.75