Question

896 ml of a mixture of CO and CO2 weigh 1.28gms at NTP. Calculate the volume of CO2 in the mixture at NTP.

Answer 1

CO = 12 + 16 = 28g
CO2 = 12 + 32 = 44g

28 g of CO has volume 22400 ml
1g of CO has volume 22400/ 28=800 ml

44 g of CO2 has volume 22400
1g of CO2 has volume 22400/ 44 ml=509.09 ml

Answer 2

Answer:

The volume of $\bold{\mathrm{CO}_{2}}$ in the mixture at NTP is 509.09 ml.

Explanation:

NTP is the abbreviation for normal temperature and pressure.  

Molecular weight of CO = 12 + 16 = 28g

Molecular weight of $\mathrm{CO}_{2}$  = 12 + 32 = 44g

At, NTP  

28 g of CO has volume = 22400 ml

Therefore, by unitary method,

1g of CO has volume = 22400/ 28 = 800 ml

And, likewise

44 g of $\mathrm{CO}_{2}$ = 22400 ml

Thus, 1g of  $\mathrm{CO}_{2}$ 22400/ 44 ml = 509.09 ml