8a2+6b+9a2+9b2+3b, find the value if a=2,b=−1.
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Answered by
8
Answer:
8a2+6b+9a2+9b2+3b
a=2,b=−1.
=8*4+6*-1+9*4+9*1+3*-1
=32-6+36+9-3
=68
Answered by
1
Answer:
41
Step-by-step explanation:
8a2+6b+9a2+9b2+3b
8×2×2+6×(-1)+9×2×2+9×(-1)×2+3×(-1)
since a = 2, b = -1
32-6+36-18-3
(-)×(+) = (-)
68-27
41
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