Question

8g of methane is placed in 5 litre container at 27 degree celsius.Find bottles constant

Answer 1

PV= Boyle Constant

But PV= nRT =w/M RT

=8/16 mol x 0.0821L atm K-1 mol-1 x 300 k

= 12.315 L atm

Hence, Boyle constant= 12.315 L atm

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Answer 2

The Boyle's constant for the gas is 12.315 L.atm

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of methane = 8 g

Molar mass of methane = 16 g/mol

Putting values in above equation, we get:

$\text{Moles of methane}=\frac{8g}{16g/mol}=0.5mol$

Boyle's Law is defined as the gas law in which pressure is inversely proportional to the volume of the gas at constant temperature.

Mathematically,

$P\propto \frac{1}{V}</p><p>Or,</p><p>PV = k</p><p><strong>To calculate the Boyle's constant, we use ideal gas equation:</strong></p><p>PV = nRT</p><p>Or, </p><p>k = nRT</p><p>where,</p><p>k = Boyle's constant = ?</p><p>T = Temperature of the gas = [tex]27^oC=[27+273]K=300K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of methane = 0.5 moles

Putting values in above equation, we get:

$k=0.5\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 300K\\\\k=12.315L.atm$

Learn more about Boyle's Law:

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