8g of methanol contain
ANS:
3g of carbon,1g of hydrogen,4g of oxygen
HOW??plz help me to solve it*
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mass of methanol= 8g
molar mass of methanol
=C + 4(H) +O
=12+4+16
=32g
moles
= mass of CH3OH / molar mass CH3OH
= 8/32
=1/4
moles = mass of H / molar mass of H
mass of H = moles × molar mass
mass of H= 1/4×1
mass of H =1/4
mass of 4 H = 4/4 =1 g
moles =mass of C / molar mass of C
mass of C = moles × molar mass
mass of C= 1/4×12
mass of C =3g
moles =mass of O / molar mass of O
mass of H = moles × molar mass
mass of H= 1/4×16
mass of H =4g
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