Question

8kx + 3y
3y = 11
$1$
​

Answer 1

Answer:

$3y = 11 \\ y = \frac{11}{3} \\ \\ 8kx + 3y = 1\\ 8kx + (3 \times \frac{11}{3} ) = 1\\ 8kx + 33 = 1 \\ 8kx = 1 - 33 \\ kx = \frac{ - 32}{8} \\ kx = - 4$