Question

8p³+q³+125r³-30pqr factorise the following​

Answer 1

$\star\:\:\bf\large\underline\blue{Question:-}$

• Factorise $8 {p}^{3} + {q}^{3} + 125 {r}^{3} - 30pqr$

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$8 {p}^{3} + {q}^{3} + 125 {r}^{3} - 30pqr$

$= {(2p)}^{3} + {(q)}^{3} + {(5r)}^{3} - 3 \times (2p \times q \times 5r)$

$= (2p + q + 5r)(4 {p}^{2} + {q}^{2} + 25 {r}^{2} - 2pq - 5qr - 10pr)$

$\star\:\:\bf\large\underline\blue{Answer:-}$

• $(2p + q + 5r)(4 {p}^{2} + {q}^{2} + 25 {r}^{2} - 2pq - 5qr - 10pr)$

Answer 2

Answer:

(2p+q+5r) ( 4p²+q²+25r²-2pq-5qr-10rp)

Step-by-step explanation:

8p³+q³+125r³-30pqr

=(2p)³+q³+(5r)³-3*(2p)(q)(5r))

Now let 2p=a ,q=b and 5r=c

then we get

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

Putting the values of a,b,c we get

(2p+q+5r) ( 4p²+q²+25r²-2pq-5qr-10rp)