Math, asked by ridagracy, 11 months ago

8sinAcosAcos2Acos4A

Answers

Answered by arvindkakade

2

sin8A=sin2(4A)
=2sin4Acos4A
=2sin2(2A)cos4A
=4sin2Acos2Acos4A
=8sinAcosAcos2Acos4A
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