Question

8th question please answer its very very urgent

Answer 1

x-2=0
x=2

When we divide any polynomial by x-2 its remaindef will be p(2)

So, remainder When;2x^3+ax^2+3x-5 is divided by x-2

p(2)=2(2)^3+a(2)^2+3(2)-5
. =16+4a+6-5
. =17+4a



Remainder when;x^3+x^2-4x-a is divided by x-2

p(2)=(2)^3+(2)^2-4(2)-a
. =8+4-8-a
. =4-a


Hence,
. 17+4a=4-a
. 4a+a=4-17
. 5a=-13
. a=-2.6 Ans.

Answer 2

Answer:

-2=0

x=2

When we divide any polynomial by x-2 its remaindef will be p(2)

So, remainder When;2x^3+ax^2+3x-5 is divided by x-2

p(2)=2(2)^3+a(2)^2+3(2)-5

. =16+4a+6-5

. =17+4a

Remainder when;x^3+x^2-4x-a is divided by x-2

p(2)=(2)^3+(2)^2-4(2)-a

. =8+4-8-a

. =4-a

Hence,

. 17+4a=4-a

. 4a+a=4-17

. 5a=-13

. a=-2.6 Ans.

Step-by-step explanation: