Question

8x+2/2x-3=4x/x-3 what is the solution​

Answer 1

Given :

$\sf \implies \dfrac{8x + 2}{2x - 3} = \dfrac{4x}{x - 3}$

To Find :

• Value of x

Solution :

$\sf\implies \frac{8x + 2}{2x - 3} = \frac{4x}{x - 3} \\ \\ \large \sf By \: cross \: multiply \\ \\ \sf\implies(x - 3)(8x + 2) = 4x(2x - 3) \\ \\ \sf\implies 8 {x}^{2} + 2x - 24x - 6 = {8x}^{2} - 12x \\ \\\sf\implies 8 {x}^{2} - 8 {x}^{2} - 22x + 12x = 6 \\ \\\sf\implies - 10x = 6 \\ \\\sf\implies x = - \frac{6}{10} \\ \\ \large\implies \boxed{\boxed{ \sf x = - \frac{3}{5} }}$

Answer 2

✯✯ QUESTION ✯✯

$\dfrac{8x+2}{2x-3}=\dfrac{4x}{x-3}$ What is The Solution...

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✰✰ ANSWER ✰✰

$\longrightarrow{\dfrac{8x+2}{2x-3}=\dfrac{4x}{x-3}}$

➜By Cross Multiply : -

$\longrightarrow{(8x+2)(x-3)=4x(2x-3)}$

$\longrightarrow{{8x}^{2}-24x+2x-6={8x}^{2}-12x}$

$\longrightarrow{-24x+2x-6=-12x}$

$\longrightarrow{-24x+2x+12x=6}$

$\longrightarrow{-22x+12x=6}$

$\longrightarrow{-10x=6}$

$\longrightarrow{x=\cancel\dfrac{6}{-10}}$

$\longrightarrow{\large{\boxed{\bold{\bold{\purple{\sf{x=\dfrac{3}{-5}}}}}}}}$