Question

8x^2-4 find zero,......


......​

Answer 1

Answer:

8x square - 4 = 0

8 x square = 4

x square= 1/2

x = √(1/2)

Answer 2

Answer:

x = ± 1/√2

Note:

★ The possible values of the variable for which the polynomial becomes zero are called its zeros.

★ To find the zeros of the polynomial p(x) , operate on p(x) = 0 .

★ A quadratic polynomial can have atmost two zeros .

★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then ;

• Sum of zeros , (α + ß) = -b/a

• Product of zeros , (αß) = c/a

★ If α and ß are the zeros of any quadratic polynomial , then it is given by ;

x² - (α + ß)x + αß

★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then they (α and ß) are also the zeros of the quadratic polynomial k(ax² + bx + c) , k≠0.

Solution:

Here,

The given quadratic polynomial is ;

8x² - 4 .

Now,

Let's find the zeros of the given quadratic polynomial by equating it to zero.

Thus,

=> 8x² - 4 = 0

=> 4(2x² - 1) = 0

=> 2x² - 1 = 0

=> 2x² = 1

=> x² = 1/2

=> x = ± 1/√2

Hence,

Required answer is : x = ± 1/√2 .