(8x^2−4y^2+6xy+5)−(3x^2−4y^2+5xy−3)
Answers
Answered by
1
the required answer is :
5x^2+xy+8
Mukkawar:
tq
Answered by
2
8x^2-4y^2+6xy+5-3x^2+4y^2-5xy+3
(8x^2-3x^2)+(-4y^2+4y^2)+(6xy-5xy)+(5+3)
5x^2+0y^2+xy+8
=5x^2+xy+8
(8x^2-3x^2)+(-4y^2+4y^2)+(6xy-5xy)+(5+3)
5x^2+0y^2+xy+8
=5x^2+xy+8
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