Math, asked by gurnoorkaurkaur1, 3 months ago

8x-[2y+{3y+2(5y-x) }]

Answers

Answered by priyabarnawal1805

0

8x-[2y+{3y+2(5y-x)}] = 0

8x-[2y+{3y+10y-2x}] = 0

8x-[2y+{13y-2x}] = 0

8x-[2y+13y-2x] = 0

8x-[15y-2x] = 0

8x-15y+2x = 0

10x-15y = 0

2x-3y = 0

x = 3y/2 and y = 2x/3

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