Question

(8x^3-3y^2)*(4x^2-y^3) solve the following question​

Answer 1

Hey Pretty Stranger!

$\large \bold \red{Here \: you \: go!}$

$\sf \: (8 {x}^{3} - 3 {y}^{2} )(4 {x}^{2} - {y}^{3} )$

$\sf \: 8 {x}^{3} (4 {x}^{2} - {y}^{3}) - 3 {y}^{2} (4 {x}^{2} - {y}^{3} )$

$\sf 32 {x}^{5} - 8 {x}^{3} {y}^{3} - 12 {x}^{2} {y}^{2} + 3 {y}^{5}$

Answer 2

$\huge\underline\mathtt{Your\:Answer}$

= $\mathtt{(8x^3-3y^2)*(4x^2-y^3)}$

= $\mathtt{8x^3(4x^2-y^3)-3y^2(4x^2-y^3)}$

= $\mathtt{32x^5 - 8x^3y^3 - 12x^2y^2 + 3y^5}$

Thank You!!