8x+4=3(x-1)+7 solve the following with linear equations
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Answered by
5
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The given problem is the polynomial of degree 1.
8x + 4 = 3(x - 1) + 7
8x + 4 = 3x - 3 + 7 = 3x + 4
On bring the variables one side and constants another side, we get,
8x - 3x = 4 - 4
5x = 0
On solving, we get,
x = 0
The given problem is the polynomial of degree 1.
8x + 4 = 3(x - 1) + 7
8x + 4 = 3x - 3 + 7 = 3x + 4
On bring the variables one side and constants another side, we get,
8x - 3x = 4 - 4
5x = 0
On solving, we get,
x = 0
Answered by
3
Step-by-step explanation:
8x+4=3(x-1)+7
or,8x+4=3x-3+7
or,8x-3x=4-4
or,5x=0
or,x=0/5
or,x=0(ans)
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