Question

8x + 5y = 9 \\ 2y = - 3x + 4​

Answer 1

Answer:

x = -2

y = 5

Step-by-step explanation:

Hi friend,

By elimination method :

8x+5y = 9---------(1) ×2

3x+2y = 4 -----(2). ×5

we get,

16x+10y = 18

15x+10y= 20

subtracting both the equations we get;

x = -2

Putting the value of x in (1)...

8×-2 +5y = 9

-16+5y = 9

5y = 9+16

5y = 25

y = 25/5

y = 5

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Hope this helped u...

☝️☝️

Answer 2

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

$\large\boxed{ \fcolorbox{blue}{red}{Elimination \: method}}$

Step-by-step explanation:

$\sf\red{8x + 5y = 9 - - - - - - (1)} \\ \sf\red{2y = - 3x + 4} \\ \sf\red{ = > 3x + 2y = 4 - - - - (2)} \\ \sf\red{(1) \times2 = > 16x + 10y = 18 - - (3)} \\ \sf\red{(2) \times 5 = > 15x + 10y = 20 - - (4)} \\ \sf\red{(4) - (3) = > (15x + 10y) - (16x + 10y) = 20 - 18} \\ \sf\red{ = > 15x + 10y - 16x - 10y = 2} \\ \sf\red{ = > - x = 2} \\ \sf\red{ = > x = - 2} \\ \sf\purple{value \: of \: x \: put \: in \: (2)} \\ \sf\red{ => 3x + 2y = 4} \\ \sf\red{ = > 2y = 4 - 3x} \\ \sf\red{ = > 2y = 4 - 3 \times ( - 2)} \\ \sf\red { = > 2y = 4 + 6} \\ \sf\red{ = > y = \frac{10}{2} } \\ \sf\red{ = > y = 5} \\ \sf\red{x = - 2,y = 5}$

$\large\boxed{ \fcolorbox{red}{purple}{hope \: it \: help \: you}}$