Question

8x²+12x-7=0-solve this by the method of factorization.​

Answer 1

$\Large{\underline{\underline{\sf{Given:}}}}$

• 8x²+12x-7

$\Large{\underline{\underline{\sf{Required\; Response:}}}}$

By The Formula of Quadratic Equation

$\frac{ - b \frac{ + }{} \sqrt{ {b}^{2} + 4ac}} {2a}$

$\frac{ - 12 \frac{ + }{} \sqrt{ {12}^{2} + 4 \times 8 \times ( - 7) } }{2 \times 8}$

$\frac{ - 12 \frac{ + }{} \sqrt{144 - 224} }{16}$

$\frac{ - 12 \frac{ + }{} \sqrt{ - 80} }{16}$

$\frac{ - 12 \frac{ + }{} 4 \sqrt{5} }{16}$

Consequently, The Roots of Quadrilateral Equation are

$\frac{ - 12 +4 \sqrt{5} }{16} \\ \frac{ - 12 - 4 \sqrt{5} }{16}$

Done :)