Question

8xcube+4x-3 plz sole this factorisations !!!

Answer 1

Let's look at your equation:
f(x) = 8x 3 + 4x - 3.
This is going to take some guesswork.
f(-1) = -8 - 4 - 3 = -15.
f(1) = 8 + 4 - 3 = 9.
f(0) = -3.
f(1/2) = 1 + 2 - 3 = 0 !!
Aha!
So I know that (x - 1/2) is a factor of 8x 3 +
4x - 3.
I can use long division to find its quotient,
which would have to be a quadratic.
x into 8x 3 goes 8x 2 times. NOTE THIS.
8x 2 times (x - 1/2) is 8x 3 - 4x 2 .
8x 3 + 4x - 3 - (8x 3 - 4x 2) is 4x 2 + 4x - 3.
Do it again:
x into 4x 2 is 4x. NOTE THIS.
4x times (x - 1/2) is 4x 2 - 2x.
4x 2 + 4x - 3 - (4x 2 - 2x) is 6x - 3.
Do it one more time:
x into 6x - 3 is 6. NOTE THIS.
6 times (x - 1/2) is 6x - 3.
6x - 3 - (6x - 3) is zero; there is no remainder,
so indeed, (x-1/2)
is a factor of f(x).
The quotient is the sum of the terms we
"noted": 8x 2 + 4x + 6.
So 8x 3 + 4x - 3 = (x - 1/2)(8x 2 + 4x + 6).
then (x-1/2) 2(4x^2+2x+3)=0
(x-1/2) (4x^2+2x+3)
solve karlo shri dhrachary formula se
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