8xcube+64ycube-zcube+24xyz
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Answer:
Step-by-step explanation:
we know that
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
given 8x³+64y³-z³+24xyz
comparing given equation with the formula
a=2x b=4y c=-z
(2x)³+(4y)³+(-z)³-3(2x)(4y)(-z)=(2x+4y-z)[4x²+16y²+z²-8xy+4yz+2xz]
therefore 8x³+64y³-z³=(2x+4y-z)(4x²+16y²+z²-8xy+4yz+2xz)
hope it helps you please mark as brianliest
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