8y cube-1 factorise
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=8y^3-1
=8y^3-1^3
=(8y-1) {(8y)^2+8y×1+1^2)} (since a^3-b^3=(a-b) (a^2+ab+b^2)
=(8y-1) (64y^2+8y+1)
HOPE. THIS ANSWER HELPS U MATE...PLEASE MARK ME AS THE BRAINLIEST.
=8y^3-1^3
=(8y-1) {(8y)^2+8y×1+1^2)} (since a^3-b^3=(a-b) (a^2+ab+b^2)
=(8y-1) (64y^2+8y+1)
HOPE. THIS ANSWER HELPS U MATE...PLEASE MARK ME AS THE BRAINLIEST.
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