Math, asked by aditya1283, 11 months ago

8y⁴-12y³+15y-4 ÷ 2y²-3y+1​

Answers

Answered by nilesh102
0

hi mate

solution : 8y⁴-12y³+15y-4 ÷ 2y²-3y+1

Equation at the end of step 1 :

(((((8•(y^4))-(12•(y®3)))+15y)-(2•y^2))-3y)+1

Step 2 :

Equation at the end of step 2 :

(((((8•(y^4))-(12•(y^3)))+15y)-2y^2)-3y)+1

Step 3 :

Equation at the end of step 3 :

(((((8•(y^4))-(2^2•3y^3))+15y)-2y^2)-3y)+1

Step 4 :

Equation at the end of step 4 :

((((2^3y^4 - (2^2•3y^3)) + 15y) - 2y^2) - 3y) + 1

Step 5 :

Polynomial Roots Calculator :

5.1 Find roots (zeroes) of :

F(y) = 8y^4-12y^3-2y^2+12y+1

of the Leading Coefficient : 1,2 ,4 ,8

of the Trailing Constant : 1

Final result :

8y^4 - 12y^3 - 2y^2 + 12y + 1

Similar questions