Question

9. (1) A vehicle starts moving on a straight line , with initial velocity 10 m/s and with constant acceleration. After moving 56m, its velocity becomes 18 m/s, he applied the breaks and come to rest in further 40.5m. Find (a) Highest speed of vehicle in journey. (b) Total time taken in journey. (c)Acceleration and the retardation, (ii) A particle moves in a straight line with acceleration 4 m/s’, and 0 initial velocity, for 3 s. Then it maintains , a uniform velocity for 6 s, and brought to rest in further 4 s, with constant retardation Find retardation and net displacement of particle. graphically solved it​

Answer 1

Answer:

Explanation:

The initial velocity of the car = u

Final velocity of the car = v

Distance covered by the car before coming to rest = 200 m

Using the equation,

v = u + at

t = (v – u)/a = 11.44 sec.

Therefore, it takes 11.44 sec for the car to stop.