9,11,20,48,?,239 find the missing number in series
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Answered by
8
9 + (1^3 + 1) = 9 + 2 = 11
11 + (2^3 + 1) = 11 + 9 = 20
20 + (3^3 + 1) = 20 + 28 = 48
48 + (4^3 + 1) = 48 + 64 + 1 = 48 + 65 = 113
113 + (5^3 + 1) = 113 + 125 + 1 = 113 + 126 = 239.
Therefore, 9, 11, 20, 48, 113, 239.
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11 + (2^3 + 1) = 11 + 9 = 20
20 + (3^3 + 1) = 20 + 28 = 48
48 + (4^3 + 1) = 48 + 64 + 1 = 48 + 65 = 113
113 + (5^3 + 1) = 113 + 125 + 1 = 113 + 126 = 239.
Therefore, 9, 11, 20, 48, 113, 239.
This help u pls mark it brainliest answers
If it help u
CristianoRonaldoCR7:
Just welcome
thanks bro
Nice Answer ronaldo
Thanks
But in the end u have written wrong answer. correct it.its 113.
Its corrected noe
Noe
Now
Thanks
Good.
Answered by
4
Hi!
Let's take first number and second numbers difference.
11 - 9 = 2 = 1³ + 1
20-11 = 9 = 2³ + 1
48 - 20 = 28 = 3³ + 1
? - 48 = 4³ +1 = 65
? - 48 = 65
? = 113 .
Now checking for last two digits.
239 - ? = 239 - 113 = 126 = 5³ +1 .
Therefore, The series 9,11,20,48,113 ,239
Let's take first number and second numbers difference.
11 - 9 = 2 = 1³ + 1
20-11 = 9 = 2³ + 1
48 - 20 = 28 = 3³ + 1
? - 48 = 4³ +1 = 65
? - 48 = 65
? = 113 .
Now checking for last two digits.
239 - ? = 239 - 113 = 126 = 5³ +1 .
Therefore, The series 9,11,20,48,113 ,239
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