Question

(9/16) ^ 6 × (64 /27) ^5 = (4/3) ^ x+2 find x ​

Answer 1

Answer:

-9

Step-by-step explanation:

(9/16) ^ 6 × (64 /27) ^5 = (4/3) ^ x+2

=>{(3/4)^2}^6×(4/3)^5=(4/3)^x+2

=>(4/3)^-2×6+5=(4/3)^x+2

As the bases are same,

-12+5=x+2

=>-7-2=x

=>-9=x