Question

9. 2 kg of ice melts when water at 100°C is poured in
a hole drilled in a block of ice. What mass of water
was used ? Given : specific heat capacity of
water = 4200 J kg-1 K-1, specific latent heat of
ice = 336 x 103 J kg-1

plsss explain it......​

Answer 1

Answer:

Explanation:

Let 'M' be the mass of ice melted and 'm' be the mass of water used

Hence M = 9.2 kg

c = 4200 J/kg K

L = 336 * 10^3 J/kg

Now the heat of water at 100°C ( i.e. 373 K) is transferred to ice to convert it into water (liquid)

i.e water of mass m undergoes temperature change and ice of mass 9.2 kg undergoes state change.

Heat given by water = heat gained

by ice

mc∆T = ML

( Assuming water's temperature decreases to 0°C , while the ice melts)

Therefore,

m*4200*(100-0) = 9.2 * 336*10^3

m = (9.2*336000)/(4200*100)

m = 7.36 kg

Hence the mass of water used is 7.36 kg