Question

(9)⅓*(27)-½/(3)^1/6*(3)-⅔
Plz solve this question completely​

Answer 1

= ( 9^⅓ × 27^-½ ) ÷ ( 3^⅙ × 3^-⅔ )

= (3^⅔ × 3^-3/2 ) ÷ ( 3^⅙ × 3^-⅔ )

= ( 3^-⅚ ) ÷ ( 3^-3/6 ) {powers of same base will be added in case of multiplication }

= 3^-⅓ {powers of same base will be subtracted in case of division}