9(3x+2y)^2-4(2x-3y)^2
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Answered by
1
Disclaimer: There is error in the Q. In (II) there should have been 2x - 3y = 12
5x + 3y = 9 -----(I)
2x - 3y = 12 ----- (II)
Add (I) and (II)
7x = 21
x = 3
Putting the value of x = 3 in (I) we get
5(3)+3y=9⇒15+3y=9⇒3y=9-15=-6⇒y=-2
Thus, (x, y) = (3, -6).
Answered by
0
Step-by-step explanation:
given
9(3x+2y)²-4(2x-3y)²
=9(9x²+4y²+12xy)-4(4x²+9y²-12xy)
=81x²+36y²+108xy-16x²-36y²-48xy
=65x²+156xy
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