Math, asked by velly6216, 9 months ago

[9+6-12-3]÷(-48) solve in evaluate

Answers

Answered by anwesha7781
9

Answer:

Here is your answer...

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Answered by MysteryUnsolved
6

Hello :D

Step-by-step explanation:

(9 + 6 - 12 - 3) \div ( - 48)

 = 15 - 12 - 3 \div ( - 48)

 = 3 - 3 \div  - 48

 = 0 \div  - 48

 = 0

0 is the answer.

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