Question

(9/6)^3/2 × 27/8 please help me soon​

Answer 1

Answer:

2

Step-by-step explanation:

Given,

${( \frac{9}{6}) }^{ (\frac{3}{2} )} \times \frac{27}{8}$

$= \sqrt[3]{ { \frac{9}{6} }^{2} } \times \frac{27}{8}$

$= \sqrt[3]{( \frac{81}{36} )} \times \frac{27}{8}$

$= \sqrt[3] \frac{ {3}^{4} }{(2 \times 3) ^{2} } \times \sqrt[3]{ { (\frac{3}{2} })^{3} }$

$= \sqrt[ {3} ]{ \frac{ {3}^{7} }{ {2}^{5} \times {3}^{2} } }$

$= \frac{9}{8} \times \sqrt[3]{ \frac{3}{ {(2 \times 3})^{2} } }$

$= \frac{9}{8} \times \sqrt[3]{ \frac{3}{36} }$

$= \frac{9}{8} \times \sqrt[3]{ \frac{1}{12} }$

$= \frac{9}{8\times \sqrt[3]{12} }$

$= \frac{9}{\sqrt[3]{{2}^{3}}\times \sqrt[3]{12} }$

$= \frac{9}{\sqrt[3]{{96} }}$

$= \frac{9}{4.5}$

$=2$

HOPE IT HELPS!!

Its was difficult to write in this way.But did it only for you. Hope you understand.

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