Math, asked by gogoiniharika594, 8 months ago

9. А 6 ohm resistance wire is doubled of by foulding calculate the new resistance the wire 30

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Answered by shrishtik512

Answer:

Resistance=ρL/A Here, Resistance=6ohm Therefore,6=ρL/A In second case, Resistance,R'=ρL'/A' As the wire is doubled so L'=L/2, A'=2A So new resistance,R'=ρL/4A=(1/4)ρL/A But ρL/A=6 So, R'=6/4=1.5Ω

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9. А 6 ohm resistance wire is doubled of by foulding calculate the new resistance the wire 30​

Answers

9. А 6 ohm resistance wire is doubled of by foulding calculate the new resistance the wire 30