Question

factorise 8 a cube minus b cube minus 12 a square b + 6 a b square​

Answer 1

$\bold{\bf{\underline{\underline{Answer:}}}}$

$\bold {\bf {∴\:(2a + b) (2a + b) (2a + b)} \:are\:the\:factors.}$

$\bold{\underline {Given:}}$

$⟹ {8a}^{3} - {b}^{3} - {12a}^{2}b + 6a{b}^{2}$

$\bold{\underline {To\:Find:}}$

${⟹}\:Factorise\: the \:given\: equation=\:?$

$\bold{\bf{\underline{\underline{Step \:by\: step \:explaination :}}}}$

$⟹ {{8a}^{3}} - {{b} ^{3}} - {{12a}^{2}b} + {6a{b}^{2}}$

$\bf{By, {(a + b)}^{3}= {a} ^{3} + {3a}^{2}b + 3a{b}^{2} + {b}^{3}}$

$\bf{Now,}$

$⟹ {{8a}^{3}} - {{b} ^{3}} - {{12a}^{2}}b + {6a{b}^{2}}$

$⟹ {{2a}^{3}} - {{b}^{3}} + 3 × {{2a}^{3}} b+ 3 × 2a{{b}^{3}}$

$\bf{According \:to\: above \:identity\:⟹}$

$⟹ {(2a + b)}^{3}$

$⟹ {(2a + b)}^{3} \:{(2a + b)}^{3} \:{(2a + b)}^{3}$

$\bf{Hence, {(2a + b)}^{3}\:{(2a + b)}^{3}\:{(2a + b)}^{3} are\: the\: factors.}$

$<h3>#Be_Brainly</h3>$

Answer 2

Answer:

mark as brainliest please