Question

[9(64^1/3+125^1/3)^3]^1/4​

Answer 1

Step-by-step explanation:

$= {(9{( {64}^{ \frac{1}{3} } + {125}^{ \frac{1}{3} }) }^{3} )}^{ \frac{1}{4} } \\ = {(9{( { {(2)}^{6} }^{ \frac{1}{3} } + { {5}^{3} }^{ \frac{1}{3} }) }^{3} )}^{ \frac{1}{4} } \\ = {(9{( {2}^{ 2} + {5}^{ }) }^{3} )}^{ \frac{1}{4} } \\ = {(9{( 4 + 5) }^{3} )}^{ \frac{1}{4} } \\ = {(9{( 9)}^{3} )}^{ \frac{1}{4} } \\ = { {9}^{4} }^{ \frac{1}{4} } \\ = 9$

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Answer 2

Answer:

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