Question

9.65 ampere current is passed for 100 minutes
during the electrolysis of molten NaCl using inert
electrode. The amount of sodium and chlorine
obtained at cathode and anode respectively are
​

Answer 1

Given info : 9.65 ampere current is passed for 100 minutes during the electrolysis of molten NaCl using inert

electrode.

To find : the amount of sodium and chlorine obtained at cathode and anode respectively.

Solution : charge , Q = it = 9.65 × 100 × 60 = 9650 × 5 C

At cathode,

Na⁺ + e¯ ⇒Na

Here it is clear that 1 mole of electron required to deposit 1 mole of Sodium.

But 1 mole of electron equivalent to 96500 C charge.

So, 96500 C charge required to deposit 1 mole of Sodium.

⇒9650 × 6 C charge deposits 1/96500 × 9650 × 6 = 0.6 mole of Sodium.

Mass of sodium = 0.6 × 23 = 13.8 g

At anode,

Cl¯ + e¯ ⇒1/2 Cl₂

1/2 mole of chlorine is deposited by 1 mole of electron.

1/2 × 1/96500 × 9650 × 6 C = 0.3 mole of chlorine is deposited by 9650 × 6 C charge.

Mass of chlorine = 0.3 × 71 = 21.3 g

Therefore amount of sodium and chlorine are 13.8 and 21.3 respectively.