if two sides of an equilateral triangle measure 1/ 4 × 3x + 1 units and 1 /3 × 4x- 1 units find the perimeter of the triangle
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Answer:
since all sides are equal of equilateral ∆ .
(3x+1)/4 = (4x-1)/3
9x+3 = 16x -4
7x = 7
x = 1
putting in any ,
side of ∆ = 3*+1/4 = 1 cm
perimeter = 3*1 = 3cm (Ans.)
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