an electric iron of heating element of resistance 88 Q is used at 220 volt for 2 hours. the electrical energy spent in unit will be
(A) 0.8
(B) 1.1
(C) 2.2
(D) 8.8
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Answer:
See,
E = P × t
= 0.22×220÷88×2
=1.1kWh
=(B)1.1units
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