Question

9.72 g of potassium chloride is dissolved in 30g of water at 70 degree celcius.Calculate the solubility of potassium chloride at that temperature.
Please reply

Answer 1

Answer:

$\bigstar{\bold{Solubility=32.4\:g/100\:g\:of\:water}}$

Explanation:

$\Large{\underline{\underline{\it{Given:}}}}$

• Mass of solute (potassium chloride ) = 9.72 g
• Mass of solvent( water) = 30 g

$\Large{\underline{\underline{\it{To\:Find:}}}}$

• Solublity of potassium chloride

$\Large{\underline{\underline{\it{Solution:}}}}$

→ Solubility is given by the equation,

  Solubilty of solute = (mass of solute/ mass of solvent) × 100

→ Substituting the given datas we get,

  Solubility = (9.72/30) × 100

  Solubility = 0.324  × 100

  Solubility = 32.4 g/100g of solvent

→ That is in 100 g of solvent, 32.4 g of solute can be dissolved at that temperature.

$\boxed{\bold{Solubility=32.4\:g/100\:g\:of\:water}}$

$\Large{\underline{\underline{{\it{Notes:}}}}$

→ Solubility is defined as the maximum amount of solute that can be dissolved in a specified amount of solvent at a specific temperature.

→ Factors affecting solubility:

• Nature of solute
• Nature of solvent
• Temperature
• Pressure

→ Only polar solutes dissolve in polar solvents and on polar solutes dissolves in non polar solvents. For example, sugar dissolves in water while naphthalene do not. Napthalene dissolves in benzene, but sugar does not.